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Sum of an AP

Authors
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    Name
    Vu Hung
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Problem Statement

Find the sum of the first 4040 terms of the arithmetic sequence

9, 13, 17, 9,\ 13,\ 17,\ \ldots

Solutions

Here a=9a=9, d=4d=4, n=40n=40. The 40th term is

l=9+394=165.l=9+39\cdot 4=165.

So

S40=402(9+165)=20174=3480.S_{40}=\frac{40}{2}(9+165)=20\cdot 174=3480.

Further Readings


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