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An Irrational Power That Is Rational

Authors
  • avatar
    Name
    Vu Hung
    Twitter

Problem Statement

Prove that an irrational number raised to the power of an irrational number can be rational, by considering 22\sqrt{2}^{\sqrt{2}}. You may assume 2\sqrt{2} is irrational.


Hints

Consider α=22\alpha = \sqrt{2}^{\sqrt{2}}. By the Law of Excluded Middle, α\alpha is either rational or irrational. Examine both cases:

  • If α\alpha is rational, you're done immediately.
  • If α\alpha is irrational, compute α2\alpha^{\sqrt{2}} and simplify.

This is a non-constructive existence proof---you prove something exists without determining which case actually holds!


Solutions

Proof by Cases:

Let α=22\alpha = \sqrt{2}^{\sqrt{2}}. We consider two exhaustive cases:

Case 1: If α=22\alpha = \sqrt{2}^{\sqrt{2}} is rational, then we have found irrational base 2\sqrt{2} and irrational exponent 2\sqrt{2} such that 22\sqrt{2}^{\sqrt{2}} is rational. Done.

Case 2: If α=22\alpha = \sqrt{2}^{\sqrt{2}} is irrational, consider:

α2=(22)2=222(exponent law)=22=2\begin{aligned} \alpha^{\sqrt{2}} &= \left(\sqrt{2}^{\sqrt{2}}\right)^{\sqrt{2}} \\ &= \sqrt{2}^{\sqrt{2} \cdot \sqrt{2}} \quad \text{(exponent law)} \\ &= \sqrt{2}^{2} \\ &= 2 \end{aligned}

Since 22 is rational and both α\alpha (irrational by case assumption) and 2\sqrt{2} (given as irrational) are irrational, we have found an example.

Conclusion: In either case, there exist irrational numbers aa and bb such that aba^b is rational. \blacksquare

Note: This proof doesn't tell us whether 22\sqrt{2}^{\sqrt{2}} is actually rational or irrational---and we don't need to know! This is the beauty of non-constructive existence proofs.


Takeaways

  • Reconstruct the full proof from the hint and the solution outline, and justify every transformation explicitly.
  • Check edge cases and verify where each assumption is used in the argument.

Further Readings

If you found this proof interesting, be sure to check out these relevant HSC booklets to sharpen your reasoning skills:


Connect with me

If you're eager for more HSC Maths insights, be sure to check out my GitHub. For deeper dives and regular tips, join my Website - Vu's Maths Hub. Let's tackle these challenging math problems together! You can also catch my daily math content on YouTube - HSC Maths Extension 1+2.